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The mean and median of economic data

The mean and median of economic data

One very high salary

8 people work in a small company.
These are their monthly salaries, in shekels, from the lowest to the highest – the last is the manager’s:
6000,6500,7000,7000,7500,8000,9000,37000\displaystyle 6000, 6500, 7000, 7000, 7500, 8000, 9000, 37000

  • The mean: 880008=11000\displaystyle {\frac{88000}{8}}={11000} ₪.
  • The median: there are two values in the middle, the fourth and the fifth, so 7000+75002=7250\displaystyle {\frac{7000+7500}{2}}={7250} ₪.

The manager’s salary is an outlier: it pulls the mean up, and 7 of the 8 workers earn less than the mean. The median hardly moves because of it: had the manager earned 12000 ₪, the median would still be 7250 ₪.

The measure of centre for salaries

The two measures of centre answer two different questions:

  • The mean – what each worker would get if all the salaries were shared out equally. It fits the question of how much is spent on salaries: 8⋅11000=88000\displaystyle {8\cdot11000}={88000} ₪ a month.
  • The median – half the workers earn less than it or exactly it, and half more. It fits the question of how much a usual worker earns.

Salaries usually include a few very high ones, so the median is lower than the mean. When the news reports “the average wage in the economy”, most workers earn less than it.

Exercise 1

9 people work in a garage.
These are their monthly salaries, in shekels:
6000,6200,6500,6500,7000,7300,8000,9500,24000\displaystyle 6000, 6200, 6500, 6500, 7000, 7300, 8000, 9500, 24000

a

Work out the mean salary.

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    b

    Find the median of the salaries.

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

      c

      A new worker asks how much people earn at the garage.
      Which measure of centre describes it better? Explain.

      The mean from a frequency table

      A chain of shops asked 20 young workers how much they get an hour:

      Hourly wage (₪)35404560
      Workers10631

      In a frequency table you multiply each value by its frequency, add, and divide by the number of values:

      xˉ=x1f1+x2f2+⋯+xkfkf1+f2+⋯+fk\displaystyle \bar{x}=\frac{x_1f_1+x_2f_2+\dots+x_kf_k}{f_1+f_2+\dots+f_k}
      xˉ=35⋅10+40⋅6+45⋅3+60⋅120=78520=39.25 \bar{x}=\frac{35\cdot10+40\cdot6+45\cdot3+60\cdot1}{20}=\frac{785}{20}=39.25
      • The mean: 39.25 ₪ an hour.
      • The median: 20 values, so it is the mean of the 10th and the 11th. Values 1–10 are 35, and the 11th is 40: 35+402=37.5\displaystyle {\frac{35+40}{2}}={37.5} ₪.
      • The mode: 35 ₪ – the wage of half the workers.
      Exercise 2

      A survey asked 20 young workers their monthly salary:

      Salary (₪)4000500060008000
      Workers5843
      a

      Work out the mean salary.

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

        b

        Find the median of the salaries.

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

          Prices over time

          A line chart shows how a price changes from month to month.
          This is the price of a kilogram of tomatoes at a greengrocer’s, in the first half of the year:

          0246810JanFebMarAprMayJunMonthPrice per kg (₪)569865
          • The highest price was in March, 9 ₪, and the lowest in January and June, 5 ₪.
          • The biggest rise: from February to March, from 6 ₪ to 9 ₪ – a rise of 36=50%\displaystyle {\frac{3}{6}}={50\%}.
          • The mean price over the half year: 5+6+9+8+6+56=396=6.5\displaystyle {\frac{5+6+9+8+6+5}{6}}={\frac{39}{6}}={6.5} ₪.
          Exercise 3

          This is the price of a litre of petrol at a filling station, in the first half of the year:

          6.57.07.58.0JanFebMarAprMayJunMonthPrice per litre (₪)77.27.57.47.17
          a

          In which month was the price highest?

          b

          Work out the mean price per litre over the half year.

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

            c

            Ron fills up 40 litres each time.
            How many shekels more does a fill-up cost in March than in January?

              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

              An axis that does not start at 0

              The monthly price of a phone plan at one company, over four years:

              01020304050602021202220232024YearPrice a month (₪)50515254

              This is the same chart, but its axis starts at 49:

              495051525354552021202220232024YearPrice a month (₪)50515254
              • Both charts hold the same data: the price rose from 50 ₪ to 54 ₪, a rise of 450=8%\displaystyle {\frac{4}{50}}={8\%}.
              • In the second chart the 2024 bar is 5 times as tall as the 2021 bar, because only the part above 49 shows.
              • Before drawing a conclusion from a chart, check where its axis starts.
              Exercise 4

              An internet company’s advert says: “Our customers have grown 6 times over!”
              Beside it is this chart:

              9901,0001,0101,0201,0301,0401,0501,060202220232024YearCustomers
              a

              By what percent did the number of customers grow from 2022 to 2024?

                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                b

                Why does the chart make the number look 6 times as big?