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The weighted mean

The weighted mean

A final mark by weights

When the values do not all count the same, work out a weighted mean: multiply each value by its weight, add, and divide by the sum of the weights.

xˉ=w1x1+w2x2+⋯+wkxkw1+w2+⋯+wk\displaystyle \bar{x}=\frac{w_1x_1+w_2x_2+\dots+w_kx_k}{w_1+w_2+\dots+w_k}

Noa’s final mark in a subject is made up of her school mark, weighted 30%, and her matriculation exam mark, weighted 70%.
Her school mark is 90, and her exam mark 80.

30⋅90+70⋅8030+70=2700+5600100=83\frac{30\cdot90+70\cdot80}{30+70}=\frac{2700+5600}{100}=83
  • When the weights are percentages adding up to 100%, each mark can be multiplied by its weight as a decimal and the products added: 0.3⋅90+0.7⋅80=27+56=83\displaystyle {0.3\cdot90+0.7\cdot80}={27+56}={83}.
  • The ordinary mean, 90+802=85\displaystyle {\frac{90+80}{2}}={85}, is not the final mark: the exam counts more, and the final mark is nearer to it.
The mean of two groups

The mean of two groups together is a weighted mean of their means, the weights being the number of people in each group.

Two classes in a year group took the same test:
10A has 20 pupils, and their mean is 80.
10B has 30 pupils, and their mean is 70.

20⋅80+30⋅7020+30=1600+210050=74\frac{20\cdot80+30\cdot70}{20+30}=\frac{1600+2100}{50}=74
  • 20⋅80\displaystyle 20\cdot80 is the sum of the marks in 10A, and 30⋅70\displaystyle 30\cdot70 that in 10B.
  • The year group’s mean is 74, not 75: it is nearer to the mean of the larger class.
A frequency table as a weighted mean

The mean of a frequency table is a weighted mean: each value’s weight is its frequency.

A falafel stall sold 100 portions in one day, in three sizes:

Price of a portion (₪)182225
Portions sold305020
30⋅18+50⋅22+20⋅25100=540+1100+500100=21.4\frac{30\cdot18+50\cdot22+20\cdot25}{100}=\frac{540+1100+500}{100}=21.4

The mean price of a portion sold: 21.4 ₪. It is also the stall’s takings, 2,140 ₪, divided by the number of portions.

The mark needed to reach a mean

When the weighted mean is known and one value is missing, the missing value is the solution of an equation.

Daniel’s school mark is 80 (30%).
He wants a final mark of 87.
What mark does he need in the exam (70%)?

Call the exam mark x\displaystyle x:

0.3⋅80+0.7x=870.3\cdot80+0.7x=87
  • 24+0.7x=87\displaystyle {24+0.7x}={87}, so 0.7x=63\displaystyle {0.7x}={63}.
  • x=630.7=90\displaystyle {x}={\frac{63}{0.7}}={90}.

Check: 0.3⋅80+0.7⋅90=24+63=87\displaystyle {0.3\cdot80+0.7\cdot90}={24+63}={87}. Daniel needs 90 in the exam.

Exercise 1

The final mark is made up of 30% school mark and 70% exam mark.

a

Work out Omer’s final mark: school 85, exam 75.

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    b

    Work out Maya’s final mark: school 60, exam 95.

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

      Exercise 2

      The mark in a college course has three parts:
      homework – 20%, a mid-term quiz – 30%, a final exam – 50%.
      Lior’s marks: homework 90, quiz 70, exam 80.

      Work out the course mark.

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

        Exercise 3

        A chain of shops has two branches.
        Branch A has 40 employees, and their mean age is 30.
        Branch B has 60 employees, and their mean age is 25.

        a

        Work out the mean age of all the chain’s employees.

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

          b

          Why is the mean not 27.5?

          Exercise 4

          200 tickets were sold for one showing at a cinema:

          Price of a ticket (₪)403020
          Tickets1206020

          Work out the mean price of a ticket.

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

            Exercise 5

            The final mark is made up of 30% school mark and 70% exam mark.
            Yael’s school mark is 70, and she wants a final mark of 84.

            Write an equation and solve it: what mark does Yael need in the exam?

            Exercise 6

            A class has 30 pupils: 12 boys and 18 girls.
            The boys’ mean in a test is 78, and the whole class’s mean is 81.

            Write an equation and solve it: what is the girls’ mean?