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Exponential equations and inequalities

Exponential equations and inequalities

The same base on both sides

An exponential function is increasing or decreasing, so it takes each value once: two powers of the same base are equal only when their exponents are.

af(x)=ag(x)  ⟺  f(x)=g(x)\displaystyle a^{f(x)}=a^{g(x)}\iff f(x)=g(x)a>0, a≠1\displaystyle a>0,\ a\neq1
  • 2x+1=32\displaystyle {2^{x+1}}={32}: 32=25\displaystyle {32}={2^5}, so 2x+1=25\displaystyle {2^{x+1}}={2^5}, x+1=5\displaystyle {x+1}={5} and x=4\displaystyle {x}={4}.
  • 9x=27\displaystyle {9^x}={27}: both are powers of 3, so 32x=33\displaystyle {3^{2x}}={3^3}, 2x=3\displaystyle {2x}={3} and x=32\displaystyle {x}={\frac{3}{2}}.
A common factor

The equation 3x+2−3x=72\displaystyle {3^{x+2}-3^x}={72} has two powers of 3 whose exponents differ by a number: 3x+2=9⋅3x\displaystyle {3^{x+2}}={9\cdot3^x}, so 3x\displaystyle 3^x is a common factor.

3x(9−1)=723^x(9-1)=72
  • Divide by 8: 3x=9=32\displaystyle {3^x}={9}={3^2}.
  • So x=2\displaystyle {x}={2}.
The substitution t=ax\displaystyle {t}={a^x}

In 4x−6⋅2x+8=0\displaystyle {4^x-6\cdot2^x+8}={0}, 4x=(22)x=(2x)2\displaystyle {4^x}={(2^2)^x}={(2^x)^2}, so with t=2x\displaystyle {t}={2^x} the equation is quadratic:

t2−6t+8=0t^2-6t+8=0
  • t=2\displaystyle {t}={2} or t=4\displaystyle {t}={4}.
  • 2x=2\displaystyle {2^x}={2} gives x=1\displaystyle {x}={1}, and 2x=4\displaystyle {2^x}={4} gives x=2\displaystyle {x}={2}.

A value of t\displaystyle t that is not positive gives no x\displaystyle x, since ax>0\displaystyle a^x>0 for every x\displaystyle x. In 9x−3x+1−54=0\displaystyle {9^x-3^{x+1}-54}={0}, with t=3x\displaystyle {t}={3^x}: t2−3t−54=0\displaystyle {t^2-3t-54}={0}, so t=9\displaystyle {t}={9} or t=−6\displaystyle {t}={-6}.

  • 3x=9\displaystyle {3^x}={9} gives x=2\displaystyle {x}={2}.
  • 3x=−6\displaystyle {3^x}={-6} has no solution.
Exponential inequalities

An increasing function keeps the order of the numbers it is given, and a decreasing one reverses it:

  • When a>1\displaystyle a>1: af(x)>ag(x)\displaystyle a^{f(x)}>a^{g(x)} exactly when f(x)>g(x)\displaystyle f(x)>g(x).
  • When 0<a<1\displaystyle 0<a<1: af(x)>ag(x)\displaystyle a^{f(x)}>a^{g(x)} exactly when f(x)<g(x)\displaystyle f(x)<g(x) – the sign turns over.

The examples below write both sides as powers of one base:

  • 2x2−3x<16=24\displaystyle {2^{x^2-3x}<16}={2^4}: the base 2 keeps the sign, x2−3x<4\displaystyle x^2-3x<4, so −1<x<4\displaystyle -1<x<4.
  • (13)x>9=(13)−2\displaystyle {\left(\frac{1}{3}\right)^x>9}={\left(\frac{1}{3}\right)^{-2}}: the base 13\displaystyle \frac{1}{3} turns the sign, so x<−2\displaystyle x<-2.
Exercise 1

Solve.

a
    b
      c
        d
          Exercise 2

          Solve by taking out a common factor.

          a
            b
              Exercise 3

              Solve by a substitution.

              a
                b
                  c
                    Exercise 4

                    Solve the inequalities.

                    a
                      b
                        c
                          d