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A circle inscribed in a triangle

A circle inscribed in a triangle

A circle inscribed in a triangle
From grade 10: every point on an angle bisector is equally far from the angle’s arms; and a point inside an angle, equally far from its arms, is on its bisector. A point’s distance from a line is the length of the perpendicular from it to the line.

A circle inscribed in a triangle is a circle that touches all three sides of the triangle. The triangle is circumscribed about the circle.

  • The centre of such a circle is equally far from the three sides – each distance is a radius, perpendicular to the side at the point of contact.
  • So the centre is on the bisector of each of the triangle’s angles.
The centre of the inscribed circle

Theorem: The three angle bisectors of a triangle meet at one point, the centre of the circle inscribed in the triangle. So every triangle has an inscribed circle.

Given: AI\displaystyle AI bisects ∠A\displaystyle \angle A, and BI\displaystyle BI bisects ∠B\displaystyle \angle B.
To prove: CI\displaystyle CI bisects ∠C\displaystyle \angle C, and the circle with centre I\displaystyle I touches the three sides.

The proof below drops perpendiculars from I\displaystyle I to the three sides and shows that they are equal:

ClaimReason
1IF=IE\displaystyle {IF}={IE}I\displaystyle I is on the bisector of the angle A\displaystyle A, so it is equally far from the angle’s arms
2IF=ID\displaystyle {IF}={ID}I\displaystyle I is on the bisector of the angle B\displaystyle B
3ID=IE\displaystyle {ID}={IE}(1), (2)
4∠ICA=∠ICB\displaystyle {\angle ICA}={\angle ICB}(3); I\displaystyle I is inside the angle C\displaystyle C and equally far from its arms, so it is on its bisector
5ID=IE=IF\displaystyle {ID}={IE}={IF}(1), (2); the circle with centre I\displaystyle I and radius ID\displaystyle ID passes through D\displaystyle D, E\displaystyle E, F\displaystyle F, and each side is perpendicular to a radius at its end – so it is a tangent to the circle
The tangent segments from the vertices

The inscribed circle touches the sides AB\displaystyle AB, BC\displaystyle BC, CA\displaystyle CA at F\displaystyle F, D\displaystyle D, E\displaystyle E. Two tangents leave each vertex, so there are two equal tangent segments:

  • AF=AE\displaystyle {AF}={AE}, BF=BD\displaystyle {BF}={BD}, CD=CE\displaystyle {CD}={CE}.
  • Each side is the sum of two such segments – for example AB=AF+FB\displaystyle {AB}={AF+FB}.

Example: AB=9\displaystyle {AB}={9}, BC=8\displaystyle {BC}={8}, CA=7\displaystyle {CA}={7}. We write AF=AE=x\displaystyle {AF}={AE}={x}; then BF=BD=9−x\displaystyle {BF}={BD}={9-x} and CE=CD=7−x\displaystyle {CE}={CD}={7-x}. The side BC\displaystyle BC is BD+DC\displaystyle BD+DC:

(9−x)+(7−x)=8⇒16−2x=8⇒x=4(9-x)+(7-x)=8\quad\Rightarrow\quad 16-2x=8\quad\Rightarrow\quad x=4
The inscribed circle of a right-angled triangle

In a right-angled triangle with legs a\displaystyle a, b\displaystyle b and hypotenuse c\displaystyle c, the radius r\displaystyle r of the inscribed circle has a simple formula:

  • Next to the right angle there is a square: two of its sides are radii, and two are the tangent segments from the right-angled vertex. So these two tangent segments equal r\displaystyle r.
  • The rest of the legs, a−r\displaystyle a-r and b−r\displaystyle b-r, are tangent segments too, and the hypotenuse is made of the two tangent segments from the acute vertices: (a−r)+(b−r)=c\displaystyle {(a-r)+(b-r)}={c}.
r\displaystyle r =\displaystyle = a+b−c2\displaystyle \frac{a+b-c}{2}

Example: in the triangle with sides 3\displaystyle 3, 4\displaystyle 4, 5\displaystyle 5: r=3+4−52=1\displaystyle {r}={\frac{3+4-5}{2}}={1}.

Exercise 1

The circle inscribed in the triangle ABC\displaystyle ABC touches the sides AB\displaystyle AB, BC\displaystyle BC, CA\displaystyle CA at F\displaystyle F, D\displaystyle D, E\displaystyle E.
AB=12\displaystyle {AB}={12}, BC=10\displaystyle {BC}={10}, CA=8\displaystyle {CA}={8}.
Find AF\displaystyle AF.

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    Exercise 2

    The legs of a right-angled triangle are 5\displaystyle 5 and 12\displaystyle 12.
    Find the radius of the circle inscribed in the triangle.

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

      Exercise 3

      The triangle ABO\displaystyle ABO is right-angled, and the point O\displaystyle O is the origin.
      The side AO\displaystyle AO is on the x\displaystyle x-axis, and the side BO\displaystyle BO on the y\displaystyle y-axis.
      A circle with centre C\displaystyle C, in the second quadrant, is inscribed in the triangle.
      The sides AO\displaystyle AO, BO\displaystyle BO and AB\displaystyle AB touch the circle at D\displaystyle D, E\displaystyle E and F\displaystyle F.

      a

      Prove: the quadrilateral OECD\displaystyle OECD is a square.

      b

      Prove: the quadrilateral ADCF\displaystyle ADCF is a kite.

      c

      D(−2,0)\displaystyle D(-2,0).
      Find the circle’s equation.

      D=(−2,0)\displaystyle D=(-2,0)

      d

      The slope of the side AB\displaystyle AB is 34\displaystyle \frac{3}{4}.

      Find ∠CAD\displaystyle \angle CAD, to two decimal places.

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

        Find the area of the trapezium ACEO\displaystyle ACEO.

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power