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Finding the mean and the standard deviation from percentages

Finding the mean and the standard deviation from percentages

An equation from each percentage

Each known percentage gives a standard score from the table, and each standard score gives an equation:

x=μ+z⋅σx=\mu+z\cdot\sigma
  • If μ\displaystyle \mu or σ\displaystyle \sigma is known – one equation is enough.
  • If neither is known – two percentages are needed, and from them a system of two equations.
Example: the mean, when the standard deviation is known

The height of 17-year-old boys is normally distributed, with standard deviation 7 cm.
80% of the boys are shorter than 182 cm.
What is the mean height?

  • The area to the left of 182 is 0.8, and the nearest in the table is 0.7995: z=0.84\displaystyle {z}={0.84}.
  • 182=μ+0.84⋅7\displaystyle {182}={\mu+0.84\cdot7}.
  • μ=182−5.88=176.12\displaystyle {\mu}={182-5.88}={176.12} cm.
Example: the mean and the standard deviation from two percentages

The time it takes to answer a quiz question is normally distributed.
15.87% of the players answer in less than 35 seconds.
5.48% of the players answer in more than 48 seconds.
What are the mean and the standard deviation?

25303540455055Answer time (seconds)
  • To the left of 35 the area is 0.1587: in the table z=−1\displaystyle {z}={-1}.
  • To the left of 48 the area is 1−0.0548=0.9452\displaystyle {1-0.0548}={0.9452}: in the table z=1.6\displaystyle {z}={1.6}.
  • Calling the mean m\displaystyle m and the standard deviation s\displaystyle s, we get:
{m−s=35m+1.6s=48\begin{cases}m-s=35\\m+1.6s=48\end{cases}
  • Subtracting the first equation from the second: 2.6s=13\displaystyle {2.6s}={13}, so s=5\displaystyle {s}={5}.
  • Substituting in the first: m=40\displaystyle {m}={40}.
Two equal percentages on the two sides

When the same percentage is above one value and below another, the mean is halfway between them – by the symmetry. Then μ\displaystyle \mu is found first, and σ\displaystyle \sigma from one equation after it.

Exercise 1

A large school checked how long a day its pupils spend on the internet.
The time is normally distributed, and the standard deviation is 25 minutes.
90% of the pupils spend less than 180 minutes a day on the internet.

a

How many minutes a day, on average, do the pupils spend on the internet? Call the mean m\displaystyle m.

    b

    What percentage of the pupils spend less than 120 minutes a day on the internet?

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

      Exercise 2

      A machine fills bottles, and the amount in a bottle is normally distributed, with mean 500 ml.
      4% of the bottles hold less than 493 ml.
      What is the standard deviation? Call it s\displaystyle s.

      Exercise 3

      The marks in a university entrance exam are normally distributed.
      10% of those who sat it scored more than 84.
      10% of those who sat it scored less than 68.

      a

      Sketch the curve and mark the data on it.

      b

      What is the mean mark?

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

        c

        What is the standard deviation? Call it s\displaystyle s.

          d

          In one year 2,000 people sat the exam. How many of them scored between one standard deviation below the mean and one standard deviation above it?

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

            Exercise 4

            The journey time of a bus on a certain route is normally distributed.
            21.19% of the journeys take less than 52 minutes.
            6.68% of the journeys take more than 75 minutes.
            What are the mean and the standard deviation? Call the mean m\displaystyle m and the standard deviation s\displaystyle s.