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The curves together; finding a locus

The curves together; finding a locus

The equation Ax2+By2+Cx+Dy+E=0\displaystyle {Ax^{2}+By^{2}+Cx+Dy+E}={0}

All the curves of this course, with their axes parallel to the coordinate axes, can be written as Ax2+By2+Cx+Dy+E=0\displaystyle {Ax^{2}+By^{2}+Cx+Dy+E}={0}. The coefficients of x2\displaystyle x^{2} and y2\displaystyle y^{2} decide which curve it is (if there is one):

  • A=B\displaystyle {A}={B} – a circle;
  • A\displaystyle A and B\displaystyle B of the same sign, different – an ellipse;
  • A\displaystyle A and B\displaystyle B of opposite signs – a hyperbola;
  • one of them 0\displaystyle 0 – a parabola.

Completing the square shows the shift. An example: x2+4y2−6x+16y+9=0\displaystyle {x^{2}+4y^{2}-6x+16y+9}={0}.

(x−3)2−9+4(y+2)2−16+9=0⇒(x−3)216+(y+2)24=1(x-3)^{2}-9+4(y+2)^{2}-16+9=0\quad\Rightarrow\quad\frac{(x-3)^{2}}{16}+\frac{(y+2)^{2}}{4}=1

An ellipse with centre (3,−2)\displaystyle (3,-2), a=4\displaystyle {a}={4} and b=2\displaystyle {b}={2} – the canonical ellipse x216+y24=1\displaystyle {\frac{x^{2}}{16}+\frac{y^{2}}{4}}={1}, shifted.

There are also degenerate cases: a point, two lines, or no point at all. For example, (x−2)29=y2\displaystyle {\frac{(x-2)^{2}}{9}}={y^{2}} is the two lines y=±x−23\displaystyle {y}={\pm\frac{x-2}{3}}.

x2+4y2−6x+16y+9=0\displaystyle x^{2}+4y^{2}-6x+16y+9=0
(3,−2)\displaystyle (3,-2)
Loci that are a parabola, an ellipse or a hyperbola

The locus of the centres of the circles that touch the x\displaystyle x-axis and pass through the point (0,2)\displaystyle (0,2).

  • The centre P(x,y)\displaystyle P(x,y) of such a circle is ∣y∣\displaystyle |y| from the x\displaystyle x-axis – this is the radius.
  • The circle passes through (0,2)\displaystyle (0,2), so P\displaystyle P’s distance from it is the radius too: x2+(y−2)2=∣y∣\displaystyle {\sqrt{x^{2}+(y-2)^{2}}}={|y|}.
  • Squared: x2+y2−4y+4=y2\displaystyle {x^{2}+y^{2}-4y+4}={y^{2}}, that is x2=4y−4=4(y−1)\displaystyle {x^{2}}={4y-4}={4(y-1)}.

This is a parabola with vertex (0,1)\displaystyle (0,1) – as expected: P\displaystyle P is as far from the point (0,2)\displaystyle (0,2) as from the line y=0\displaystyle {y}={0}, which is exactly the definition of a parabola with a focus and a directrix.

In the same way a condition on the sum of the distances from two points gives an ellipse, and a condition on their difference – a hyperbola.

x2=4y−4\displaystyle x^{2}=4y-4
(0,2)\displaystyle (0,2)
Exercise 1

Which curve does each equation describe – a line, two lines, a circle, an ellipse, a hyperbola or a parabola? (x−2)29=y2−1\displaystyle {\frac{(x-2)^{2}}{9}}={y^{2}-1}, (x−2)29=y2+1\displaystyle {\frac{(x-2)^{2}}{9}}={y^{2}+1}, (x−2)29=y2\displaystyle {\frac{(x-2)^{2}}{9}}={y^{2}}, (x−2)29=−y2+1\displaystyle {\frac{(x-2)^{2}}{9}}={-y^{2}+1}, (x−2)29=y−1\displaystyle {\frac{(x-2)^{2}}{9}}={y-1}.

Exercise 2
Complete the square in x2−4x\displaystyle x^{2}-4x and in −9y2−18y\displaystyle -9y^{2}-18y.

Which curve is x2−9y2−4x−18y−14=0\displaystyle {x^{2}-9y^{2}-4x-18y-14}={0}? Find its centre, and complete the square in the card.

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    The curve and its centre:

    Exercise 3

    Find the locus of the points as far from (0,3)\displaystyle (0,3) as from the line y=−3\displaystyle {y}={-3}.

    y=−3\displaystyle y=-3
    (0,3)\displaystyle (0,3)

    Exercise 4

    Find the locus of the points whose distances from (0,4)\displaystyle (0,4) and (0,−4)\displaystyle (0,-4) add up to 10\displaystyle 10.

    (0,4)\displaystyle (0,4)
    (0,−4)\displaystyle (0,-4)

    Exercise 5

    Find the locus of the points whose distance from the point (4,0)\displaystyle (4,0) is half their distance from the line x=16\displaystyle {x}={16}.

    x=16\displaystyle x=16
    (4,0)\displaystyle (4,0)

    Which curve is it? What are its vertices?