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A hyperbola with a line and a circle

A hyperbola with a line and a circle

A line and a hyperbola

Here too we solve the system. A line and a hyperbola may have two common points, one or none, and there are two special cases:

  • A line parallel to an asymptote meets the hyperbola at only one point and crosses it – it is no tangent. After substituting, x2\displaystyle x^{2} cancels and a first-degree equation is left.
  • A line through the centre whose slope is steeper than the asymptotes’ does not meet the hyperbola at all.

An example: x2−y2=16\displaystyle {x^{2}-y^{2}}={16} and y=x−2\displaystyle {y}={x-2} – parallel to the asymptote y=x\displaystyle {y}={x}.

x2−(x−2)2=16⇒4x−4=16⇒x=5x^{2}-(x-2)^{2}=16\quad\Rightarrow\quad4x-4=16\quad\Rightarrow\quad x=5

One point: (5,3)\displaystyle (5,3).

x2−y2=16\displaystyle x^{2}-y^{2}=16
y=x−2\displaystyle y=x-2
y=x\displaystyle y=x
y=−x\displaystyle y=-x
(5,3)\displaystyle (5,3)
A line touching a hyperbola

When substituting gives a quadratic equation, the line touches when its discriminant is 0\displaystyle 0.

An example: for which values of n\displaystyle n does the line y=2x+n\displaystyle {y}={2x+n} touch the hyperbola x24−y2=1\displaystyle {\frac{x^{2}}{4}-y^{2}}={1}?

  • x2−4(2x+n)2=4\displaystyle {x^{2}-4(2x+n)^{2}}={4}, that is −15x2−16nx−4n2−4=0\displaystyle {-15x^{2}-16nx-4n^{2}-4}={0}.
  • The discriminant: 256n2−4⋅15⋅(4n2+4)=16n2−240\displaystyle {256n^{2}-4\cdot15\cdot(4n^{2}+4)}={16n^{2}-240}.
  • 16n2=240\displaystyle {16n^{2}}={240}, so n=±15\displaystyle {n}={\pm\sqrt{15}}.
A circle and a hyperbola

A circle with its centre on the x\displaystyle x-axis and a canonical hyperbola: as with the ellipse, isolate y2\displaystyle y^{2} in one equation and put it into the other.

An example: x2−y2=7\displaystyle {x^{2}-y^{2}}={7} and x2+y2=25\displaystyle {x^{2}+y^{2}}={25}. Add the equations: 2x2=32\displaystyle {2x^{2}}={32}, so x=±4\displaystyle {x}={\pm4}, and y2=9\displaystyle {y^{2}}={9}. Four points: (±4,±3)\displaystyle (\pm4,\pm3).

x2−y2=7\displaystyle x^{2}-y^{2}=7
x2+y2=25\displaystyle x^{2}+y^{2}=25
Exercise 1

Find the points common to the hyperbola x2−y2=9\displaystyle {x^{2}-y^{2}}={9} and the line y=2x−6\displaystyle {y}={2x-6}, and mark them on the board.

a
    b
    x2−y2=9\displaystyle x^{2}-y^{2}=9
    y=2x−6\displaystyle y=2x-6

    Exercise 2

    The hyperbola x2−y2=9\displaystyle {x^{2}-y^{2}}={9} and the line y=2x\displaystyle {y}={2x}.

    a
      b

      Explain the result with the slopes of the asymptotes.

      Exercise 3

      For which values of n\displaystyle n does the line y=x+n\displaystyle {y}={x+n} touch the hyperbola x24−y23=1\displaystyle {\frac{x^{2}}{4}-\frac{y^{2}}{3}}={1}?

        Exercise 4

        Find the points common to the hyperbola x216−y29=1\displaystyle {\frac{x^{2}}{16}-\frac{y^{2}}{9}}={1} and the circle x2+y2=25\displaystyle {x^{2}+y^{2}}={25}.

          The circle passes through the hyperbola’s foci. How can you see this from the equations?

          Exercise 5

          The line y=34x+1\displaystyle {y}={\frac{3}{4}x+1} and the hyperbola x216−y29=1\displaystyle {\frac{x^{2}}{16}-\frac{y^{2}}{9}}={1}. Without solving: at most how many common points can they have? Why?

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

            / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power