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The parabola: a locus and its canonical equation

The parabola: a locus and its canonical equation

Focus and directrix

A parabola is the locus of all the points in the plane whose distance from a given point, the focus F\displaystyle F, equals their distance from a given line, the directrix.

To get a simple equation, we choose the coordinate system like this:

  • the x\displaystyle x-axis passes through the focus, perpendicular to the directrix;
  • the origin is halfway between the focus and the directrix.

If the distance between the focus and the directrix is p\displaystyle p, the focus is F(p2,0)\displaystyle F\left(\frac{p}{2},0\right) and the directrix x=−p2\displaystyle {x}={-\frac{p}{2}}. The distance of P(x,y)\displaystyle P(x,y) from the directrix is ∣x+p2∣\displaystyle \left|x+\frac{p}{2}\right|, so the condition is:

(x−p2)2+y2=∣x+p2∣\sqrt{\left(x-\frac{p}{2}\right)^{2}+y^{2}}=\left|x+\frac{p}{2}\right|

Squaring: x2−px+p24+y2=x2+px+p24\displaystyle {x^{2}-px+\frac{p^{2}}{4}+y^{2}}={x^{2}+px+\frac{p^{2}}{4}}, and almost everything cancels. What is left is the canonical equation of the parabola:

y2=2px\displaystyle y^{2}=2px
Properties from the equation

From the equation y2=2px\displaystyle {y^{2}}={2px} we see:

  • Symmetry – if (x,y)\displaystyle (x,y) is on the parabola, so is (x,−y)\displaystyle (x,-y): y\displaystyle y appears only squared. The x\displaystyle x-axis is the axis of symmetry.
  • The vertex – the origin, the parabola’s point nearest the directrix.
  • The direction – when p>0\displaystyle p>0, x=y22p≥0\displaystyle {x}={\frac{y^{2}}{2p}\ge0}: the parabola opens to the right, towards the focus. When p<0\displaystyle p<0 it opens to the left.

An example: y2=12x\displaystyle {y^{2}}={12x}. Here 2p=12\displaystyle {2p}={12}, so p=6\displaystyle {p}={6}: the focus is F(3,0)\displaystyle F(3,0) and the directrix x=−3\displaystyle {x}={-3}. The point (3,6)\displaystyle (3,6) is on the parabola, 6\displaystyle 6 away both from the focus and from the directrix.

y2=12x\displaystyle y^{2}=12x
x=−3\displaystyle x=-3
F=(3,0)\displaystyle F=(3,0)
(3,6)\displaystyle (3,6)
A focus on the y\displaystyle y-axis

When the y\displaystyle y-axis is chosen through the focus, x\displaystyle x and y\displaystyle y swap: the focus is F(0,p2)\displaystyle F\left(0,\frac{p}{2}\right), the directrix y=−p2\displaystyle {y}={-\frac{p}{2}}, and the equation x2=2py\displaystyle {x^{2}}={2py}.

This is grade 9’s parabola: y=12px2\displaystyle {y}={\frac{1}{2p}x^{2}}. For example, y=14x2\displaystyle {y}={\frac{1}{4}x^{2}}, that is x2=4y\displaystyle {x^{2}}={4y}, has p=2\displaystyle {p}={2}: the focus (0,1)\displaystyle (0,1) and the directrix y=−1\displaystyle {y}={-1}.

A shifted parabola

When the focus and the directrix are not in the canonical place, the same method gives a shifted parabola.

An example: the focus (3,2)\displaystyle (3,2) and the directrix x=−1\displaystyle {x}={-1}.

(x−3)2+(y−2)2=(x+1)2⇒(y−2)2=8x−8=8(x−1)(x-3)^{2}+(y-2)^{2}=(x+1)^{2}\quad\Rightarrow\quad(y-2)^{2}=8x-8=8(x-1)

This is the parabola y2=8x\displaystyle {y^{2}}={8x} shifted 1\displaystyle 1 to the right and 2\displaystyle 2 up: the vertex is (1,2)\displaystyle (1,2), halfway between the focus and the directrix.

Exercise 1

The parabola: y2=8x\displaystyle {y^{2}}={8x}.

a

What are p\displaystyle p and the focus?

p\displaystyle p

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    b

    Write the directrix’s equation on the board.

    y2=8x\displaystyle y^{2}=8x

    Exercise 2

    A parabola’s focus is F(5,0)\displaystyle F(5,0), and its directrix x=−5\displaystyle {x}={-5}.
    Write the parabola’s equation.

    x=−5\displaystyle x=-5
    F=(5,0)\displaystyle F=(5,0)

    Exercise 3

    A parabola’s focus is (0,2)\displaystyle (0,2), and its directrix y=−2\displaystyle {y}={-2}.
    Write the parabola’s equation.

    y=−2\displaystyle y=-2
    F=(0,2)\displaystyle F=(0,2)

    Exercise 4
    By the definition, the distance from the focus equals the distance from the directrix – and that one is easy to work out.

    The point P\displaystyle P is on the parabola y2=16x\displaystyle {y^{2}}={16x}, and xP=9\displaystyle {x_P}={9}.

    a

    What is yP\displaystyle y_P? (There are two such points.)

    b
    The distance of P\displaystyle P from the focus

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

      Exercise 5

      A parabola’s focus is (4,−1)\displaystyle (4,-1), and its directrix x=0\displaystyle {x}={0}.
      Write the parabola’s equation.

      x=0\displaystyle x=0
      F=(4,−1)\displaystyle F=(4,-1)

      Exercise 6

      The parabola y2=2px\displaystyle {y^{2}}={2px} passes through the point (2,−4)\displaystyle (2,-4).

      a
      Find p\displaystyle p.
        b

        What are the focus and the directrix of the parabola?