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Concavity: how the rate of change changes

Concavity: how the rate of change changes

A slope that grows and a slope that shrinks

The derivative says how fast the function changes. That rate can change too: as you move along the graph from left to right, the slope of the tangent can grow or shrink. The board below shows the graphs of f(x)=x2\displaystyle {f(x)}={x^2} and g(x)=−x2\displaystyle {g(x)}={-x^2}:

f(x)=x2\displaystyle f(x)=x^{2}
g(x)=−x2\displaystyle g(x)=-x^{2}

The slopes of the tangents at a few points:

x\displaystyle x−2\displaystyle -2−1\displaystyle -10\displaystyle 01\displaystyle 12\displaystyle 2
f′(x)=2x\displaystyle {f'(x)}={2x}−4\displaystyle -4−2\displaystyle -20\displaystyle 02\displaystyle 24\displaystyle 4
g′(x)=−2x\displaystyle {g'(x)}={-2x}4\displaystyle 42\displaystyle 20\displaystyle 0−2\displaystyle -2−4\displaystyle -4
  • The slope of f\displaystyle f grows all the time: the graph bends upwards, like ∪\displaystyle \cup.
  • The slope of g\displaystyle g shrinks all the time: the graph bends downwards, like ∩\displaystyle \cap.
Concave up, concave down

The way the graph bends depends on whether its slope grows or shrinks:

  • A function is concave up (∪\displaystyle \cup) on an interval where the derivative f′\displaystyle f' rises – the rate of change keeps growing.
  • A function is concave down (∩\displaystyle \cap) on an interval where the derivative f′\displaystyle f' falls – the rate of change keeps shrinking.
  • These intervals are the intervals of concavity of the function.

Concavity does not depend on whether the function rises or falls: a rising function can be concave up (rising faster and faster) or concave down (rising more and more slowly).

Tangents and chords

A chord is a segment joining two points on the graph. The board below shows the graph of f(x)=x2\displaystyle {f(x)}={x^2}, the tangent y=2x−1\displaystyle {y}={2x-1} at the point (1,1)\displaystyle (1,1), and the chord from (0,0)\displaystyle (0,0) to (1,1)\displaystyle (1,1), which lies on the line y=x\displaystyle {y}={x}:

f(x)=x2\displaystyle f(x)=x^{2}
y=2x−1\displaystyle y=2x-1
y=x\displaystyle y=x
  • For a function that is concave up, the graph is above its tangents, and the chords are above the graph.
  • For a function that is concave down – the other way round: the graph is below its tangents, and the chords are below the graph.
A fall that grows steeper

Careful: when a function falls and grows steeper, its slope shrinks. For example, the slopes −1\displaystyle -1, −3\displaystyle -3, −6\displaystyle -6 keep getting smaller. So a fall that grows steeper is concave down, and a fall that grows gentler is concave up.

Example: x3\displaystyle x^3

The example below finds the intervals of concavity of f(x)=x3\displaystyle {f(x)}={x^3}:

  • f′(x)=3x2\displaystyle {f'(x)}={3x^2} – a parabola that falls where x<0\displaystyle x<0 and rises where x>0\displaystyle x>0.
  • So f\displaystyle f is concave down where x<0\displaystyle x<0, and concave up where x>0\displaystyle x>0.
f(x)=x3\displaystyle f(x)=x^{3}
  • f\displaystyle f rises everywhere, but in two different ways: left of 0 the rise grows gentler, and right of 0 it grows steeper.
  • At the point (0,0)\displaystyle (0,0) the graph passes from concave down to concave up.
Exercise 1

A car sets off.
The table gives the distance s\displaystyle s it has covered (in metres) after t\displaystyle t seconds:

t\displaystyle t012345
s\displaystyle s01491625
a

Work out the average speed between t=1\displaystyle {t}={1} and t=2\displaystyle {t}={2}.

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    b

    Work out the average speed between t=3\displaystyle {t}={3} and t=4\displaystyle {t}={4}.

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

      c

      Is the graph of s\displaystyle s against t\displaystyle t concave up or concave down? Give your reason.

      Exercise 2

      The function is f(x)=x3−3x\displaystyle {f(x)}={x^3-3x}.
      Its derivative, f′(x)=3x2−3\displaystyle {f'(x)}={3x^2-3}, falls where x<0\displaystyle x<0 and rises where x>0\displaystyle x>0.

      a

      Mark on the graph the point where the graph passes from concave down to concave up.

      f(x)=x3−3x\displaystyle f(x)=x^{3}-3x

      b

      Write the intervals of concavity of f\displaystyle f.
      On the interval 0<x<1\displaystyle 0<x<1 the function falls. Does the fall grow steeper or gentler there?

      Exercise 3

      The function is f(x)=1x\displaystyle {f(x)}={\frac{1}{x}}, on the interval x>0\displaystyle x>0.

      a

      Work out the slope of the tangent to the graph where x=1\displaystyle {x}={1}.

      f(x)=1x\displaystyle f(x)=\frac{1}{x}

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

        b

        Work out the slope of the tangent to the graph where x=2\displaystyle {x}={2}.

        f(x)=1x\displaystyle f(x)=\frac{1}{x}

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

          c

          f′(x)=−1x2\displaystyle {f'(x)}={-\frac{1}{x^2}}.
          Does f′\displaystyle f' rise or fall on the interval x>0\displaystyle x>0?
          Is f\displaystyle f concave up or concave down there?

          Exercise 4

          The function is f(x)=4−x2\displaystyle {f(x)}={4-x^2}.
          The point (1,3)\displaystyle (1,3) is on its graph.

          a

          Write on the board the equation of the tangent to the graph at the point (1,3)\displaystyle (1,3).

          f(x)=4−x2\displaystyle f(x)=4-x^{2}
          (1,3)\displaystyle (1,3)

          b

          Is the tangent above the graph or below it?
          How does that fit the concavity of f\displaystyle f?