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The graphs of f, f′ and f″

The graphs of f, f′ and f″

What each graph tells

Each derivative describes the rate of change of the function before it, so the links between f\displaystyle f and f′\displaystyle f' hold between f′\displaystyle f' and f′′\displaystyle f'' too:

GraphWhat you seeWhat it says about f\displaystyle f
f′\displaystyle f'above / below the x\displaystyle x-axisf\displaystyle f rises / falls
f′\displaystyle f'crosses the x\displaystyle x-axisan extremum point of f\displaystyle f
f′\displaystyle f'rises / fallsf\displaystyle f is concave up / concave down
f′\displaystyle f'an extremum pointan inflection point of f\displaystyle f
f′′\displaystyle f''above / below the x\displaystyle x-axisf\displaystyle f is concave up / concave down
f′′\displaystyle f''crosses the x\displaystyle x-axisan inflection point of f\displaystyle f

An extremum point of f′\displaystyle f' is an inflection point of f\displaystyle f: there the slope of f\displaystyle f stops growing and starts shrinking, or the other way round.

Example: x3−3x\displaystyle x^3-3x and its two derivatives

The board below shows three graphs: f(x)=x3−3x\displaystyle {f(x)}={x^3-3x}, the derivative f′(x)=3x2−3\displaystyle {f'(x)}={3x^2-3} and the second derivative f′′(x)=6x\displaystyle {f''(x)}={6x}.

f(x)=x3−3x\displaystyle f(x)=x^{3}-3x
y=3x2−3\displaystyle y=3x^{2}-3
y=6x\displaystyle y=6x
  • f′\displaystyle f' crosses the x\displaystyle x-axis at x=−1\displaystyle {x}={-1} and at x=1\displaystyle {x}={1} – there are the extremum points of f\displaystyle f.
  • f′\displaystyle f' has a minimum at x=0\displaystyle {x}={0}, and there f′′\displaystyle f'' crosses the x\displaystyle x-axis – the inflection point of f\displaystyle f, (0,0)\displaystyle (0,0).
  • f′′<0\displaystyle f''<0 where x<0\displaystyle x<0: there f′\displaystyle f' falls and f\displaystyle f is concave down. f′′>0\displaystyle f''>0 where x>0\displaystyle x>0: f′\displaystyle f' rises and f\displaystyle f is concave up.
Which graph is which

Given three graphs – of a function, of its derivative and of its second derivative – you tell them apart by asking which graph describes the rate of change of which:

  • Graph g\displaystyle g is the derivative of graph h\displaystyle h if g\displaystyle g crosses the x\displaystyle x-axis exactly where h\displaystyle h has an extremum, g\displaystyle g is above the axis where h\displaystyle h rises and below it where h\displaystyle h falls.
  • Check every pair. The function is the graph that is the derivative of none of the others; the second derivative is the graph that no other graph is the derivative of.
  • For a polynomial, each derivative lowers the degree by 1: if one of the graphs is a parabola and another a straight line, the line is the derivative of the parabola.

To show that no other order works, it is enough to find, for each other order, a place where the link fails – for example, a graph that rises where its “derivative” is below the axis.

Exercise 1

The boards show the graph of f(x)=x3−6x2+9x\displaystyle {f(x)}={x^3-6x^2+9x}.

a

Write the derivative f′(x)\displaystyle f'(x) on the board. Its graph appears beside the graph of f\displaystyle f.

f(x)=x3−6x2+9x\displaystyle f(x)=x^{3}-6x^{2}+9x

b

Write the second derivative f′′(x)\displaystyle f''(x) on the board.

f(x)=x3−6x2+9x\displaystyle f(x)=x^{3}-6x^{2}+9x

c

Where does f′\displaystyle f' cross the x\displaystyle x-axis, and what does f\displaystyle f have there?
Where does f′′\displaystyle f'' cross the x\displaystyle x-axis, and what does f\displaystyle f have there?

Exercise 2

The board shows the graph of the derivative f′(x)=x2−4x+3\displaystyle {f'(x)}={x^2-4x+3} of a function f\displaystyle f.
The graph of f\displaystyle f itself is not given.

a

Mark on the graph the points where it crosses the x\displaystyle x-axis, and its extremum point.

y=x2−4x+3\displaystyle y=x^{2}-4x+3

b

At x=1\displaystyle {x}={1} and at x=3\displaystyle {x}={3}, f\displaystyle f has extremum points: what is the type of each?
Where is f\displaystyle f concave up, and where concave down?
What is the x\displaystyle x-coordinate of the inflection point of f\displaystyle f?

The x\displaystyle x of the inflection point

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    Exercise 3

    The function f\displaystyle f can be differentiated twice for every x\displaystyle x.
    It has only two extremum points: a minimum where x=3\displaystyle {x}={3}, and a maximum where x=5\displaystyle {x}={5}.

    a

    What is the sign of f′\displaystyle f' where x<3\displaystyle x<3, where 3<x<5\displaystyle 3<x<5 and where x>5\displaystyle x>5?

    b

    A possible derivative is f′(x)=−(x−3)(x−5)\displaystyle {f'(x)}={-(x-3)(x-5)}.
    Solve the inequality f′(x)>0\displaystyle f'(x)>0, and check that the answer fits the part before.

      c

      The board shows the graph of f′(x)=−(x−3)(x−5)\displaystyle {f'(x)}={-(x-3)(x-5)}.
      Mark its extremum point.

      y=−(x−3)(x−5)\displaystyle y=-(x-3)(x-5)

      d

      What does f\displaystyle f have at the point you marked?
      Explain why every function like f\displaystyle f – a minimum at 3, a maximum at 5 – has an inflection point between 3 and 5.

      Exercise 4

      The board shows three graphs: f(x)=x3−3x2\displaystyle {f(x)}={x^3-3x^2} and two graphs whose formulas are hidden.
      One of them is the graph of f′\displaystyle f', and the other – of f′′\displaystyle f''.

      a

      Write on the board the formula of each hidden graph.

      f(x)=x3−3x2\displaystyle f(x)=x^{3}-3x^{2}
      y= ?\displaystyle y=\,?
      y= ?\displaystyle y=\,?

      b

      How can you tell from the graphs themselves, with no formulas, which is f′\displaystyle f' and which is f′′\displaystyle f''?