Investigating trigonometric functions
Investigating trigonometric functions
Investigating a trigonometric function goes through the same steps as any investigation, and starts by asking whether the function is periodic:
- The period: if is periodic, investigate it on an interval of one period, for example , and repeat the graph. If not – on the interval the question gives.
- The domain: , a denominator and a root leave out points or intervals.
- The derivative: solve in the interval – a trigonometric equation, whose solutions in the interval are a finite number of points.
- A table of signs of : the extremum points and where the function rises and falls.
- The second derivative: the sign of gives the intervals of concavity, and a point where it changes is an inflection point.
- A sketch: the points you found, then repeated by the period.
The example below investigates on the interval . The function is not periodic, because of the term .
- . where , and in the interval: or .
| + | 0 | − | 0 | + | |
| rises | maximum | falls | minimum | rises |
- ; .
- : negative where – concave down; positive where – concave up.
- At the concavity changes: an inflection point .
- At the ends of the interval: – a minimum at an end, – a maximum at an end.
The graph winds around the line (dashed): adds up to 2 to it and takes up to 2 from it. It crosses the line where – at the inflection point and at the ends of the interval.
The example below investigates – the root of a trigonometric function:
- The domain: , that is , and in every such period: . Between these intervals the function has no values.
- The period is , so it is enough to investigate the interval .
- , and inside the interval where , that is .
- is positive where and negative where : a maximum .
- At the ends of the interval, and , the function reaches its least value: minimum points at the ends of the domain.
- There the denominator of is 0 and the derivative is not defined: the graph leaves the ends with a vertical tangent, like at 0.
All the functions of the family have the same inflection points, but only some of them have extremum points:
- , with no : the concavity changes at every , for every value of .
- , and where . This equation has a solution only when .
- When the derivative changes sign, and there are extremum points; when or – there are none.
On the board: , and .
- : the graph rises and falls, with extremum points.
- : , and the function rises. At the points the derivative is 0 but does not change sign – these are horizontal inflection points.
- : , and the function rises with no extremum points; the inflection points stayed at the same .
You can sketch the graph of even before differentiating, from the properties of its two factors:
- , so : the graph is caught between the parabolas and – its “envelope”.
- where , and where : there the graph touches the envelope.
- The zeros are the zeros of , .
- : the function is odd.
The function is not periodic: the factor repeats itself, but the factor makes the waves bigger the further you go from 0. In , by contrast, adds waves of a fixed height to the parabola.
Investigate the function on the interval .
Find .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Solve the equation in the interval.
Find .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Solve the equation in the interval.
Mark on the graph the extremum points and the inflection points on the board.
Write where rises and falls and the intervals of concavity of in the interval.
What is the period of ?
Investigate the function on the interval – one period of it.
Find , and write it with .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Solve the equation in the interval.
Find .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Solve the equation in the interval.
Mark on the graph the extremum points and the inflection points on the board.
Investigate the function on the interval .
Find .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Solve the equation in the interval.
Work out .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Mark the extremum points on the graph.
Why is the function defined for every ?
Show that is odd, and explain how this fits the extremum points you found.
Investigate the function on the interval .
Find .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Solve the equation in the interval.
Find .
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
Mark on the graph the extremum points and the inflection points on the board.
Write the kind of each extremum point, and the greatest and the least value of on the interval.
In the family of the example, belongs to which ? How does this explain why has extremum points?
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power
/ – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power