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Practice: the second derivative

Practice: the second derivative

1

Find the second derivative of each function.

a

f(x)=x4−2x3+5x\displaystyle f(x)=x^{4}-2x^{3}+5x

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

    / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

    b

    f(x)=xx+1\displaystyle f(x)=\frac{x}{x+1}

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

      c

      f(x)=(2x−1)3\displaystyle f(x)=(2x-1)^{3}

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

        2

        The function is f(x)=x3+3x2−9x\displaystyle {f(x)}={x^3+3x^2-9x}.
        Its second derivative is f′′(x)=6x+6\displaystyle {f''(x)}={6x+6}.

        a

        Solve the inequality f′′(x)>0\displaystyle f''(x)>0: where is f\displaystyle f concave up?

          b

          Mark the inflection point on the graph.

          f(x)=x3+3x2−9x\displaystyle f(x)=x^{3}+3x^{2}-9x

          3

          The function is f(x)=x33−x2−3x+1\displaystyle {f(x)}={\frac{x^3}{3}-x^2-3x+1}.
          Its derivative is f′(x)=x2−2x−3\displaystyle {f'(x)}={x^2-2x-3}.

          a

          Solve the equation f′(x)=0\displaystyle {f'(x)}={0}.

            b

            f′′(x)=2x−2\displaystyle {f''(x)}={2x-2}.
            Work out f′′\displaystyle f'' at the two points you found.

            f(x)=x33−x2−3x+1\displaystyle f(x)=\frac{x^{3}}{3}-x^{2}-3x+1

              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

              f(x)=x33−x2−3x+1\displaystyle f(x)=\frac{x^{3}}{3}-x^{2}-3x+1

                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                c

                Mark the extremum points on the graph.

                f(x)=x33−x2−3x+1\displaystyle f(x)=\frac{x^{3}}{3}-x^{2}-3x+1

                d

                Write the type of each extremum point, from the sign of f′′\displaystyle f''.

                4

                The function is f(x)=x4−6x3+12x2\displaystyle {f(x)}={x^4-6x^3+12x^2}.

                a

                f(x)=x4−6x3+12x2\displaystyle f(x)=x^{4}-6x^{3}+12x^{2}

                  / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                  / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                  b

                  Solve the equation f′′(x)=0\displaystyle {f''(x)}={0}.

                    c

                    Mark the inflection points on the graph.

                    f(x)=x4−6x3+12x2\displaystyle f(x)=x^{4}-6x^{3}+12x^{2}

                    5

                    The function is f(x)=x4−4x3+6x2\displaystyle {f(x)}={x^4-4x^3+6x^2}.

                    a

                    f(x)=x4−4x3+6x2\displaystyle f(x)=x^{4}-4x^{3}+6x^{2}

                      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                      / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                      b

                      Solve the equation f′′(x)=0\displaystyle {f''(x)}={0}.

                        c

                        Is the point you found an inflection point? Give your reason.

                        6

                        The board shows the graph of the derivative f′(x)=x(x−2)2\displaystyle {f'(x)}={x(x-2)^2} of a function f\displaystyle f.

                        a

                        Mark on the graph the points where it meets the x\displaystyle x-axis, and its extremum points.

                        y=x(x−2)2\displaystyle y=x(x-2)^{2}

                        b

                        Which points of f\displaystyle f do the points you marked belong to?
                        Write the extremum points of f\displaystyle f and their types, and the x\displaystyle x-coordinates of the inflection points of f\displaystyle f.

                        7

                        A body moves along a straight line by s(t)=t3−9t2+24t\displaystyle {s(t)}={t^3-9t^2+24t}, with t≥0\displaystyle t\geq0 (metres, seconds).

                        a

                        Find the acceleration a(t)=s′′(t)\displaystyle {a(t)}={s''(t)}.

                        s(t)=t3−9t2+24t\displaystyle s(t)=t^{3}-9t^{2}+24t

                          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                          b

                          When is the acceleration 0?

                            c

                            Work out the speed at that moment.
                            At that moment the speed is at its smallest: why?

                            s(t)=t3−9t2+24t\displaystyle s(t)=t^{3}-9t^{2}+24t

                              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                              8

                              The family of functions is f(x)=x4+ax3\displaystyle {f(x)}={x^4+ax^3}, where a\displaystyle a is a parameter.

                              a

                              Find f′′(x)\displaystyle f''(x), in terms of a\displaystyle a.

                              f(x)=x4+ax3\displaystyle f(x)=x^{4}+ax^{3}

                                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                                b

                                For which value of a\displaystyle a does the function have an inflection point at x=1\displaystyle {x}={1}?

                                  9

                                  The board shows the graph of f(x)=x4−2x2\displaystyle {f(x)}={x^4-2x^2} and two graphs whose formulas are hidden: of f′\displaystyle f' and of f′′\displaystyle f''.
                                  Write on the board the formula of each hidden graph.

                                  f(x)=x4−2x2\displaystyle f(x)=x^{4}-2x^{2}
                                  y= ?\displaystyle y=\,?
                                  y= ?\displaystyle y=\,?

                                  10

                                  For each claim choose: always, sometimes or never – and prove it.
                                  A function of degree two has an inflection point.
                                  A function of degree three has an inflection point.
                                  A function of degree four has an inflection point.

                                  11

                                  The function f\displaystyle f can be differentiated twice, and it has a minimum point at x0\displaystyle x_0.
                                  Explain why f′′(x0)\displaystyle f''(x_0) is not negative.