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Practice: derivatives and investigation

Practice: derivatives and investigation

1

Differentiate. In part e, find the second derivative.

a

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    b

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      c

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

        d

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

          / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

          e

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            2

            The function f(x)=xln⁡x\displaystyle {f(x)}={x\ln x} is given.

            a

            Calculate the slope of the tangent to the graph at the point where x=e\displaystyle {x}={e}.

            f(x)=xln⁡x\displaystyle f(x)=x\ln x

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              b

              f(e)=e\displaystyle {f(e)}={e}.
              Write the equation of the tangent to the graph at the point (e,e)\displaystyle (e,e).

              f(x)=xln⁡x\displaystyle f(x)=x\ln x
              (2.718,2.718)\displaystyle (2.718,2.718)

              3

              The function f(x)=(x+1)e−x\displaystyle {f(x)}={(x+1)e^{-x}} is given.

              a

              Find f′(x)\displaystyle f'(x).

              f(x)=(x+1)e−x\displaystyle f(x)=(x+1)e^{-x}

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                b

                Find the extremum point of the function, and its type.

                c

                Find f′′(x)\displaystyle f''(x).

                f(x)=(x+1)e−x\displaystyle f(x)=(x+1)e^{-x}

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                  / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                  d

                  Find where the function is concave up.

                    e

                    Mark the extremum point and the inflection point on the graph.

                    f(x)=(x+1)e−x\displaystyle f(x)=(x+1)e^{-x}

                    4

                    The function f(x)=ln⁡(x2−1)\displaystyle {f(x)}={\ln(x^2-1)} is given.

                    a

                    Find the domain.

                      b

                      Find f′′(x)\displaystyle f''(x).

                      f(x)=ln⁡(x2−1)\displaystyle f(x)=\ln(x^{2}-1)

                        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                        / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                        c

                        Show that the function is concave down throughout its domain.
                        Is the function even? Give a reason.

                        d

                        Add a row for each of the vertical asymptotes.

                        f(x)=ln⁡(x2−1)\displaystyle f(x)=\ln(x^{2}-1)

                        5

                        The functions g(x)=ex2−2x\displaystyle {g(x)}={e^{x^2-2x}} and h(x)=ln⁡(x2−2x+2)\displaystyle {h(x)}={\ln(x^2-2x+2)} are given.

                        a

                        Mark the extremum point of each function on the graph.

                        g(x)=ex2−2x\displaystyle g(x)=e^{x^{2}-2x}
                        h(x)=ln⁡(x2−2x+2)\displaystyle h(x)=\ln(x^{2}-2x+2)

                        b

                        Explain, without differentiating, why both functions have an extremum point at the same x\displaystyle x, and why both are minima.

                        6

                        The graph below shows the derivative of a function f\displaystyle f: f′(x)=g(x)=(x−2)ex\displaystyle {f'(x)}={g(x)}={(x-2)e^x}.

                        a

                        On the graph of f′\displaystyle f', mark the point whose x\displaystyle x is the x-coordinate of the extremum point of f\displaystyle f, and the point whose x\displaystyle x is the x-coordinate of the inflection point of f\displaystyle f.

                        g(x)=(x−2)ex\displaystyle g(x)=(x-2)e^{x}

                        b

                        Find where f\displaystyle f increases.

                          c

                          Find the type of the extremum point of f\displaystyle f, and where f\displaystyle f is concave up. Give the reasons from the graph of f′\displaystyle f'.

                          7

                          The function f(x)=x2+aln⁡x\displaystyle {f(x)}={x^2+a\ln x} is given, with a\displaystyle a a parameter.
                          The function has an extremum point where x=2\displaystyle {x}={2}.

                          a

                          Find f′(x)\displaystyle f'(x).

                          f(x)=x2+aln⁡x\displaystyle f(x)=x^{2}+a\ln x

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                            b

                            Find a\displaystyle a.

                            c

                            Substitute the a\displaystyle a you found, and calculate the y-coordinate of the extremum point.

                            f(x)=x2−8ln⁡x\displaystyle f(x)=x^{2}-8\ln x

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                              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                              d

                              Mark the extremum point on the graph.

                              f(x)=x2−8ln⁡x\displaystyle f(x)=x^{2}-8\ln x

                              8

                              The concentration of a substance in the blood, t\displaystyle t hours after it was taken, is C(t)=50te−0.25t\displaystyle {C(t)}={50te^{-0.25t}} milligrams per litre (t≥0\displaystyle t\geq0).
                              When is the concentration highest, and what is it?

                              a

                              Find C′(t)\displaystyle C'(t).

                              C(t)=50te−0.25t\displaystyle C(t)=50te^{-0.25t}

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                                b

                                Solve the equation C′(t)=0\displaystyle {C'(t)}={0}.

                                c

                                Calculate the highest concentration, rounded to two decimal places.

                                C(t)=50te−0.25t\displaystyle C(t)=50te^{-0.25t}

                                  / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                                  / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power