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The geometric mean, the first term and the ratio

The geometric mean, the first term and the ratio

The geometric mean

In a geometric sequence an−1=anq\displaystyle {a_{n-1}}={\frac{a_n}{q}} and an+1=an⋅q\displaystyle {a_{n+1}}={a_n\cdot q}, so their product is an2\displaystyle a_n^2:

an2\displaystyle a_n^2 =\displaystyle = an−1⋅an+1\displaystyle a_{n-1}\cdot a_{n+1}n≥2\displaystyle n\geq2
  • When the terms are positive, an=an−1⋅an+1\displaystyle {a_n}={\sqrt{a_{n-1}\cdot a_{n+1}}}: the term is the geometric mean of its neighbours.
  • In the sequence 4,6,9\displaystyle 4, 6, 9: 62=36=4⋅9\displaystyle {6^2}={36}={4\cdot9}.
The ratio from two terms

The quotient of two terms gives a power of q\displaystyle q:

  • a3=12\displaystyle {a_3}={12} and a6=96\displaystyle {a_6}={96}: a6a3=q3=8\displaystyle {\frac{a_6}{a_3}}={q^3}={8}, so q=2\displaystyle {q}={2} and a1=124=3\displaystyle {a_1}={\frac{12}{4}}={3}.
  • a2=8\displaystyle {a_2}={8} and a4=32\displaystyle {a_4}={32}: q2=4\displaystyle {q^2}={4}, so q=2\displaystyle {q}={2} or q=−2\displaystyle {q}={-2} – two sequences: 4,8,16,32,…\displaystyle 4, 8, 16, 32, \ldots and −4,8,−16,32,…\displaystyle -4, 8, -16, 32, \ldots
  • An even power of q\displaystyle q gives two solutions, and an odd power – one.
A system in a1\displaystyle a_1 and q\displaystyle q

In a geometric sequence the sum of the first and the third term is 50, and the sum of the second and the fourth is 150.

  • a1+a1q2=50\displaystyle {a_1+a_1q^2}={50} and a1q+a1q3=150\displaystyle {a_1q+a_1q^3}={150}.
  • The second equation is q⋅(a1+a1q2)=150\displaystyle {q\cdot(a_1+a_1q^2)}={150}, that is q⋅50=150\displaystyle {q\cdot50}={150}, so q=3\displaystyle {q}={3}.
  • a1(1+9)=50\displaystyle {a_1(1+9)}={50}, so a1=5\displaystyle {a_1}={5}: the sequence 5,15,45,135,…\displaystyle 5, 15, 45, 135, \ldots
Three neighbouring terms

Three neighbouring terms of a geometric sequence are handy to write as bq\displaystyle \frac{b}{q}, b\displaystyle b, bq\displaystyle bq: in their product q\displaystyle q cancels.

The product of three neighbouring terms is 216, and their sum is 26.

  • bq⋅b⋅bq=b3=216\displaystyle {\frac{b}{q}\cdot b\cdot bq}={b^3}={216}, so b=6\displaystyle {b}={6}.
  • 6q+6+6q=26\displaystyle {\frac{6}{q}+6+6q}={26}, that is 6q2−20q+6=0\displaystyle {6q^2-20q+6}={0}, so q=3\displaystyle {q}={3} or q=13\displaystyle {q}={\frac{1}{3}}.
  • The numbers: 2,6,18\displaystyle 2, 6, 18 or 18,6,2\displaystyle 18, 6, 2.
Exercise 1

In a geometric sequence a2=6\displaystyle {a_2}={6} and a5=162\displaystyle {a_5}={162}.
Find a1\displaystyle a_1 and q\displaystyle q.

    Exercise 2

    In a geometric sequence a3=18\displaystyle {a_3}={18} and a5=162\displaystyle {a_5}={162}.
    Find a1\displaystyle a_1 and q\displaystyle q (two sequences).

      Exercise 3

      The numbers x\displaystyle x, x+6\displaystyle x+6, 9x\displaystyle 9x (in this order) are three neighbouring terms of a geometric sequence.
      Find x\displaystyle x (two solutions), and the ratio for each.

        Exercise 4

        The product of three neighbouring terms of a geometric sequence is 1,000, and their sum is 35.
        Call them 10q\displaystyle \frac{10}{q}, 10\displaystyle 10, 10q\displaystyle 10q. Find q\displaystyle q and the numbers.

          Exercise 5

          In a geometric sequence the sum of the second and the third term is 36, and the sum of the third and the fourth is 108.
          Find a1\displaystyle a_1 and q\displaystyle q.