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Recap: basic trigonometric equations

Recap: basic trigonometric equations

The general solution

A trigonometric equation has infinitely many solutions, since the functions repeat. The general solution writes all of them with a whole number k\displaystyle k:

  • sin⁡x=a\displaystyle {\sin x}={a} (when −1≤a≤1\displaystyle -1\le a\le1): two angles at the same height on the unit circle, α\displaystyle \alpha and π−α\displaystyle \pi-\alpha.
x=α+2πkorx=π−α+2πk\displaystyle x=\alpha+2\pi k\quad\text{or}\quad x=\pi-\alpha+2\pi k
  • cos⁡x=a\displaystyle {\cos x}={a}: two angles mirrored in the x\displaystyle x-axis, α\displaystyle \alpha and −α\displaystyle -\alpha.
x\displaystyle x =\displaystyle = ±α+2πk\displaystyle \pm\alpha+2\pi k
  • tan⁡x=a\displaystyle {\tan x}={a}: one angle in every half turn.
x\displaystyle x =\displaystyle = α+πk\displaystyle \alpha+\pi k

Here α\displaystyle \alpha is one angle with the value a\displaystyle a, and k\displaystyle k is any whole number.

sin⁡f(x)=sin⁡g(x)\displaystyle {\sin f(x)}={\sin g(x)}

The same idea works when both sides are sines of expressions:

  • sin⁡f(x)=sin⁡g(x)\displaystyle {\sin f(x)}={\sin g(x)}: f(x)=g(x)+2πk\displaystyle {f(x)}={g(x)+2\pi k} or f(x)=π−g(x)+2πk\displaystyle {f(x)}={\pi-g(x)+2\pi k}.
  • cos⁡f(x)=cos⁡g(x)\displaystyle {\cos f(x)}={\cos g(x)}: f(x)=±g(x)+2πk\displaystyle {f(x)}={\pm g(x)+2\pi k}.
  • tan⁡f(x)=tan⁡g(x)\displaystyle {\tan f(x)}={\tan g(x)}: f(x)=g(x)+πk\displaystyle {f(x)}={g(x)+\pi k}.

An example: cos⁡3x=cos⁡x\displaystyle {\cos3x}={\cos x}.

  • 3x=x+2πk\displaystyle {3x}={x+2\pi k} or 3x=−x+2πk\displaystyle {3x}={-x+2\pi k}.
  • x=πk\displaystyle {x}={\pi k} or x=πk2\displaystyle {x}={\frac{\pi k}{2}}.
  • Every multiple of π\displaystyle \pi is also a multiple of π2\displaystyle \frac{\pi}{2}, so the solution is x=πk2\displaystyle {x}={\frac{\pi k}{2}}.
A multiple angle inside the sine

When the function holds 2x\displaystyle 2x, solve for 2x\displaystyle 2x first and only then divide – 2πk\displaystyle 2\pi k too:

sin⁡2x=32\displaystyle {\sin2x}={\frac{\sqrt{3}}{2}}

  • 2x=π3+2πk\displaystyle {2x}={\frac{\pi}{3}+2\pi k} or 2x=2π3+2πk\displaystyle {2x}={\frac{2\pi}{3}+2\pi k}.
  • x=π6+πk\displaystyle {x}={\frac{\pi}{6}+\pi k} or x=π3+πk\displaystyle {x}={\frac{\pi}{3}+\pi k}.

After dividing, the period shrinks to π\displaystyle \pi: every full turn holds four solutions.

Degrees, and an inverse function
  • In degrees, 360∘\displaystyle 360^\circ takes the place of 2π\displaystyle 2\pi and 180∘\displaystyle 180^\circ of π\displaystyle \pi: the solution of sin⁡x=12\displaystyle {\sin x}={\frac{1}{2}} is x=30∘+360∘k\displaystyle {x}={30^\circ+360^\circ k} or x=150∘+360∘k\displaystyle {x}={150^\circ+360^\circ k}.
  • When the value is not from the table, the angle α\displaystyle \alpha is written with the inverse function. The solution of sin⁡x=13\displaystyle {\sin x}={\frac{1}{3}}: x=sin⁡−113+2πk\displaystyle {x}={\sin^{-1}\frac{1}{3}+2\pi k} or x=π−sin⁡−113+2πk\displaystyle {x}={\pi-\sin^{-1}\frac{1}{3}+2\pi k}.
  • The number comes from a calculator (in radian mode): sin⁡−113≈0.34\displaystyle \sin^{-1}\frac{1}{3}\approx0.34.
Exercise 1

Solve.

    Exercise 2

    Solve.

      Exercise 3

      Solve.

        Exercise 4

        Solve.

          Exercise 5

          Solve in degrees.

            Exercise 6

            Solve. Write the solution with cos⁡−1\displaystyle \cos^{-1}.