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Practice: trigonometric equations

Practice: trigonometric equations

1

Solve.

    2

    Solve.

      3

      Solve.

        4

        Solve.

          5

          Solve.

            6

            Solve.

              7

              Solve.

                8

                Solve.

                  9

                  Solve in the interval 0≤x≤2π\displaystyle 0\le x\le2\pi.

                    10

                    Solve in degrees, in the interval 0∘≤x≤360∘\displaystyle 0^\circ\le x\le360^\circ.

                      11

                      A pupil solved sin⁡xcos⁡x=12sin⁡x\displaystyle {\sin x\cos x}={\frac{1}{2}\sin x} like this: he divided both sides by sin⁡x\displaystyle \sin x, got cos⁡x=12\displaystyle {\cos x}={\frac{1}{2}}, and so x=±π3+2πk\displaystyle {x}={\pm\frac{\pi}{3}+2\pi k}.
                      Which solutions is he missing, and why?