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Equations and areas with the distributive law

Equations and areas with the distributive law

Once you can open brackets with the extended distributive law and the short multiplication formulas, you can solve two new kinds of problems:

  • equations in which x2\displaystyle x^{2} cancels once the brackets are opened;
  • comparing the areas of shapes whose sides are expressions.
Equations where x2\displaystyle x^{2} cancels
With a different coefficient of x2\displaystyle x^{2} on each side, x2\displaystyle x^{2} does not cancel: that is a quadratic equation, and it needs other methods.

When x2\displaystyle x^{2} appears on both sides with the same coefficient, it cancels, and a linear equation is left. First open the brackets, then subtract x2\displaystyle x^{2} from both sides:

(x+3)(x−2)=x2+7x2+x−6=x2+7/−x2x−6=7/+6x=13 \begin{aligned}(x+3)(x-2)&=x^{2}+7\\ x^{2}+x-6&=x^{2}+7 &&/-x^{2}\\ x-6&=7 &&/+6\\ x&=13\end{aligned}

Check in the original equation: (13+3)(13−2)=16⋅11=176\displaystyle {(13+3)(13-2)}={16\cdot11}={176} and 132+7=169+7=176\displaystyle {13^{2}+7}={169+7}={176} – equal.

Equations with the short multiplication formulas
A minus before an expression from a formula: write the expression in brackets first, −(x2−4x+4)\displaystyle -(x^{2}-4x+4), and only then open them.

The short multiplication formulas open the brackets the same way:

(x+4)2=(x−2)2+36x2+8x+16=x2−4x+4+36/−x28x+16=−4x+40/+4x−1612x=24/:12x=2 \begin{aligned}(x+4)^{2}&=(x-2)^{2}+36\\ x^{2}+8x+16&=x^{2}-4x+4+36 &&/-x^{2}\\ 8x+16&=-4x+40 &&/+4x-16\\ 12x&=24 &&/:12\\ x&=2\end{aligned}

Check: (2+4)2=36\displaystyle {(2+4)^{2}}={36} and (2−2)2+36=0+36=36\displaystyle {(2-2)^{2}+36}={0+36}={36}.

Exercise 1

Open the brackets on each side, solve the equation, and check the solution by substitution.

a
    b
      c
        d
          e
            Comparing areas

            To compare two areas, subtract one from the other and simplify the difference. For example, a square’s side is x\displaystyle x; one pair of its sides is lengthened by 3 and the other pair shortened by 3, which makes a rectangle. xxx+3x−3

            • The square’s area: x2\displaystyle x^{2}.
            • The rectangle’s area: (x+3)(x−3)=x2−9\displaystyle {(x+3)(x-3)}={x^{2}-9}.
            • The difference: x2−(x2−9)=9\displaystyle {x^{2}-(x^{2}-9)}={9} – the square is bigger by 9, for every x\displaystyle x.
            The growth of an area

            When x\displaystyle x is left in the difference, the answer depends on x\displaystyle x. A square’s side, x\displaystyle x, grows by 2:

            • its area grows by (x+2)2−x2=x2+4x+4−x2=4x+4\displaystyle {(x+2)^{2}-x^{2}}={x^{2}+4x+4-x^{2}}={4x+4};
            • if the area grew by 24, then 4x+4=24\displaystyle {4x+4}={24}, so 4x=20\displaystyle {4x}={20} and x=5\displaystyle {x}={5}. Check: 72−52=49−25=24\displaystyle {7^{2}-5^{2}}={49-25}={24}.
            Exercise 2

            Write an expression for the difference of the areas and simplify it, then answer the questions.

            a

            One rectangle is x\displaystyle x long and x+5\displaystyle x+5 wide; another is x+2\displaystyle x+2 long and x+3\displaystyle x+3 wide.
            Which area is bigger, and by how much?
            Does the answer depend on x\displaystyle x?

              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

              / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

              b

              A square’s side is x\displaystyle x.
              One pair of its sides is lengthened by 4 and the other pair shortened by 2, which makes a rectangle.
              For which x\displaystyle x are the areas of the square and of the rectangle equal?

                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power

                c

                A square’s side grew by 3 cm, and its area grew by 51 cm².
                What was the side at first?
                Check your answer.

                  / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – check and a new line · * – times · ^ – power, ↓ – end of the power

                  / – fraction bar · Tab or the arrows – between numerator and denominator, then a note above or below · Enter – a new line · * – times · ^ – power, ↓ – end of the power