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The similarity theorems

The similarity theorems

The similarity theorems

The similarity theorems say which data are enough to know that two triangles are similar, without checking all three angles and all three sides.

  • They are like the congruence theorems, and even have the same names: AA, SAS, SSS.
  • In congruence the sides are equal; in similarity they are in the same ratio.
The similarity theorem AA
In a quadrilateral, equal angles are not enough: in a square and in a long rectangle all the angles are right, and they are not similar.

The similarity theorem AA (angle, angle): if two angles of one triangle are equal to two angles of another triangle, the triangles are similar.

  • The third angle is equal too: the angles of a triangle add up to 180∘\displaystyle 180^\circ, so it is what the other two leave.
  • No side needs to be known.
The similarity theorem SAS

The similarity theorem SAS (side, angle, side): if two sides of one triangle are in the same ratio to two sides of another triangle, and the angles between them are equal, the triangles are similar.

  • An example: one triangle has sides of 4\displaystyle 4 and 6\displaystyle 6 with an angle of 50∘\displaystyle 50^\circ between them; another has sides of 6\displaystyle 6 and 9\displaystyle 9 with an angle of 50∘\displaystyle 50^\circ between them.
  • 64=96=1.5\displaystyle {\frac{6}{4}}={\frac{9}{6}}={1.5}, and the angles between them are equal: the triangles are similar, with the ratio of similarity 1.5\displaystyle 1.5.
The similarity theorem SSS

The similarity theorem SSS (side, side, side): if the three sides of one triangle are in the same ratio to the three sides of another triangle, the triangles are similar.

  • Sort each triangle’s sides from the shortest to the longest, and divide each side by the side in its place in the other triangle.
  • An example: 3\displaystyle 3, 5\displaystyle 5, 6\displaystyle 6 and 6\displaystyle 6, 10\displaystyle 10, 12\displaystyle 12: every quotient is 2\displaystyle 2, so the triangles are similar.
Exercise 1

Are the triangles similar? If so, write by which similarity theorem.

a

Two angles of one triangle: 40∘\displaystyle 40^\circ and 75∘\displaystyle 75^\circ.
Two angles of another triangle: 75∘\displaystyle 75^\circ and 65∘\displaystyle 65^\circ.

b

The sides of one triangle: 4\displaystyle 4, 5\displaystyle 5, 7\displaystyle 7.
The sides of another triangle: 12\displaystyle 12, 15\displaystyle 15, 21\displaystyle 21.

c

One triangle has sides of 3\displaystyle 3 and 5\displaystyle 5, with an angle of 60∘\displaystyle 60^\circ between them.
Another triangle has sides of 6\displaystyle 6 and 10\displaystyle 10, with an angle of 60∘\displaystyle 60^\circ between them.

d

The sides of one triangle: 2\displaystyle 2, 3\displaystyle 3, 4\displaystyle 4.
The sides of another triangle: 4\displaystyle 4, 6\displaystyle 6, 9\displaystyle 9.

A segment parallel to a side

A segment parallel to a side of a triangle cuts off a small triangle similar to it.

In triangle ABC\displaystyle ABC, the point D\displaystyle D is on the side AB\displaystyle AB, the point E\displaystyle E is on the side AC\displaystyle AC, and DE∥BC\displaystyle DE\parallel BC.
Prove: △ADE∼△ABC\displaystyle \triangle ADE\sim\triangle ABC.

The proof below shows that two angles of triangle ADE\displaystyle ADE are equal to two angles of triangle ABC\displaystyle ABC, and uses the similarity theorem AA:

ClaimReason
1DE∥BC\displaystyle DE\parallel BCGiven
2∠ADE=∠ABC\displaystyle {\angle ADE}={\angle ABC}(1); corresponding angles between parallel lines are equal
3∠AED=∠ACB\displaystyle {\angle AED}={\angle ACB}(1); corresponding angles between parallel lines are equal
4△ADE∼△ABC\displaystyle \triangle ADE\sim\triangle ABC(2), (3); the similarity theorem AA
A calculation with the parallel segment
Careful: the side corresponding to AD\displaystyle AD is the whole of AB\displaystyle AB, not DB\displaystyle DB.

In the same drawing, given: AD=3\displaystyle {AD}={3}, AB=9\displaystyle {AB}={9}, BC=12\displaystyle {BC}={12}.
How long is DE\displaystyle DE?

  • By the order of the letters in △ADE∼△ABC\displaystyle \triangle ADE\sim\triangle ABC, the side AD\displaystyle AD corresponds to AB\displaystyle AB, and DE\displaystyle DE to BC\displaystyle BC.
  • A proportion: DE12=39\displaystyle {\frac{DE}{12}}={\frac{3}{9}}.
  • Cross-multiplying: 9⋅DE=36\displaystyle {9\cdot DE}={36}, so DE=4\displaystyle {DE}={4}.
Exercise 2

The segments AB\displaystyle AB and CD\displaystyle CD cross at the point O\displaystyle O.
Given: AC∥BD\displaystyle AC\parallel BD.

a. Prove: △AOC∼△BOD\displaystyle \triangle AOC\sim\triangle BOD.

b

Also given: AO=4\displaystyle {AO}={4}, OB=6\displaystyle {OB}={6}, AC=5\displaystyle {AC}={5}.
Find BD\displaystyle BD.

The height of a tree from its shadow

A tree’s height can be measured without climbing it: measure its shadow, and the shadow of a stick whose height is known.

A stick 1.5\displaystyle 1.5 metres long stands upright on the ground, and its shadow is 2\displaystyle 2 metres long.
At the same hour, the shadow of a tree nearby is 12\displaystyle 12 metres long.
How tall is the tree?

  • The sun is very far away, so its rays reaching the stick and the tree are parallel. The angle between a sun ray and the ground (α\displaystyle \alpha) is the same at the stick and at the tree.
  • The stick and the tree are upright, so the angles at the ground below them are equal too: both are right.
  • By the similarity theorem AA the two triangles are similar, so h1.5=122\displaystyle {\frac{h}{1.5}}={\frac{12}{2}}.
  • 122=6\displaystyle {\frac{12}{2}}={6}, so h=1.5⋅6=9\displaystyle {h}={1.5\cdot6}={9}: the tree is 9\displaystyle 9 metres tall.
Exercise 3

Noa, who is 1.6\displaystyle 1.6 metres tall, stands near a building.
Her shadow is 2.4\displaystyle 2.4 metres long, and at the same hour the building’s shadow is 30\displaystyle 30 metres long.
How tall is the building? Write a proportion and solve it.

Exercise 4

In triangle ABC\displaystyle ABC, the point D\displaystyle D is on the side AB\displaystyle AB, the point E\displaystyle E is on the side AC\displaystyle AC, and DE∥BC\displaystyle DE\parallel BC.
Given: AD=4\displaystyle {AD}={4}, DB=6\displaystyle {DB}={6}, DE=5\displaystyle {DE}={5}.
Find BC\displaystyle BC.